Calculations and content checked: 2026-10-09
A matching shape is only the starting point
Imagine testing a geometrically similar, 1 m model of a 10 m surface body moving at 5 m/s. Should the model speed be one tenth of the full-scale speed, or should it stay the same? We will compare Reynolds and Froude numbers to answer a narrower question: what speed matches each ratio? This is an illustrative scaling exercise, not a performance prediction for a particular vessel.
Use ρ = 1000 kg/m³, μ = 0.001 Pa·s and g = 9.81 m/s² for both cases. The kinematic viscosity is ν = 10⁻⁶ m²/s. L denotes a representative body length throughout, not an open-channel depth.
1. Establish the full-scale reference
Refull = 1000 × 5 × 10 / 0.001 = 50,000,000
Frfull = 5 / √(9.81 × 10) ≈ 0.5048
The first ratio concerns viscosity; the second concerns gravity. A body-length Fr below one does not label the surrounding flow as subcritical open-channel flow. Check the chosen length and the conditions attached to a calculator's regime description.
2. Choose a speed that matches Fr
With equal gravity, matching Fr requires vmodel/√Lmodel = vfull/√Lfull. Define λ = Lmodel/Lfull = 0.1. The required speed ratio is √λ.
At this speed, model Fr is approximately 0.5048, but model Re is approximately 1,581,139. Check the ratio directly: Remodel/Refull = λ3/2 ≈ 0.03162. The viscosity-related scale is only about 3.16% of the full-scale value despite the matching Fr.
3. Choose a speed that matches Re
With the same fluid, matching Re requires vmodelLmodel = vfullLfull. Therefore the model speed must be 5 × 10/1 = 50 m/s. Model Fr then becomes 50/√9.81 ≈ 15.9638, about 31.62 times full-scale Fr.
| Condition | Speed (m/s) | Re | Fr |
|---|---|---|---|
| Same speed as full scale | 5 | 5,000,000 | 1.5964 |
| Match Fr | 1.5811 | ≈ 1,581,139 | 0.5048 |
| Match Re | 50 | 50,000,000 | 15.9638 |
The Fr-matched row uses the unrounded speed 5√0.1. Entering the displayed 1.5811 produces a small last-digit difference.
4. What would matching both require?
Keeping the Fr-matched speed while matching Re would require νmodel = λ3/2νfull = 3.1623×10⁻⁸ m²/s. This is an algebraic requirement, not a recommendation for an available working fluid. If density also changes, use μ = ρν consistently.
Adjusting speed alone cannot match every important dimensionless ratio. Surface tension may require a Weber-number comparison; compressibility may require Mach number. Choose the phenomenon to reproduce before deciding which additional ratios matter.
Keep a comparison record
- State whether λ means model/full scale or its reciprocal.
- Record the definition of L, geometric ratios and boundary conditions.
- List both matched ratios and unmatched ratios.
- Avoid applying circular-pipe Reynolds thresholds or open-channel Froude classifications to body-length calculations.
A matching Fr alone does not validate total drag, skin friction or full-scale performance. The table quantifies the scaling mismatch under equal-fluid and equal-gravity assumptions; it is a starting point for deciding what further evidence is needed.
Formula and concept references: NASA Glenn — Reynolds Number · MIT OpenCourseWare — Similitude, §5.2 (PDF). The input sets and cross-checks are worked examples constructed for this site, not quoted property tables or experimental results.